A

B

C

Pythagore\ Activité\ de\ découverte

On\ constate\ que:\ 
ABC\ est\ rectangle\ en\ A\ \Leftrightarrow AB²+AC²=BC²

MathsEnClair.com

AB = 5 (slider from 0 to 30, step 1)
AC = 12 (slider from 0 to 30, step 1)
BC = 11 (slider from 0 to 30, step 1)
A = (-18.81543970365511, 1.8139188019589252)
a_1: abs(AB)
B = Point(Circle[A, abs(AB)])
a = Segment(A, B)
c = Circle(A, AC)
d = Circle(B, BC)
C = Intersect(c, d, 1)
b = Segment(A, C)
e = Segment(C, B)
α = Angle(B, A, C)
texte4: "AB=" + (LaTeX[AB]) + ""
texte5: "AC=" + (LaTeX[AC]) + ""
texte6: "BC=" + (LaTeX[BC]) + ""
ABauCarre: (AB * AB)
ACaucarre: (AC * AC)
BCauCarre: (BC * BC)
texte7: "AB^2=" + (LaTeX[ABauCarre]) + ""
texte8: "AC^2=" + (LaTeX[ACaucarre]) + ""
texte9: "BC^2=" + (LaTeX[BCauCarre]) + ""
β = Angle(B, A, C)